Open the tap and watch the flask. When the colour changes, note the burette reading, then use V₁M₁ = V₂M₂ to find the concentration. Slow to single drops near the end point.
Controls
Acid in the flask (acid : base mole ratio)
Indicator
Readings
- Flask pH
- 1.10
- NaOH added
- 0.00mL
- End-point reading
- —
- Calculated concentration
- —
- True concentration
- 0.080M
- Error
- —
- Acid : base
- 1 : 1
How to use this simulation
- The flask holds 25 mL of acid and an indicator, the burette 0.10 M NaOH. Open the tap and the yellow dot on the right-hand graph walks along the pH curve.
- Near the end point the message above turns to “go drop by drop”. Close the tap and press “Add one drop” to catch the exact moment the colour changes.
- When the colour flips, “End-point reading” and “Calculated concentration” light up. Compare with “True concentration” to see your error.
- Now change the indicator, then switch the acid to H₂SO₄. With a 1 : 2 mole ratio the same acid concentration needs twice as much alkali. Check it.
Filling a glass until it overflows
Say you do not know how much water a glass holds. Pour in a spoonful at a time, count the spoonfuls, and the one that makes it overflow tells you the size. The glass is the unknown, the spoon is the known measure, and the overflow is the signal.
A titration does exactly this in chemistry. The acid in the flask is the unknown, the alkali in the burette has a known concentration, and the “overflow” signal is the indicator changing colour. Read how many mL of alkali it took and the acid’s concentration follows.
In the simulation the flask always holds 25 mL of acid. Move the concentration slider and the equivalence point shifts away from 20.0 mL, yet the same technique catches it every time.
The words of titration
Mixing these terms up costs marks, so settle them once.
| Term | Meaning | In the simulation |
|---|---|---|
| Titrant | The solution of known concentration in the burette | NaOH, 0.10 M |
| Analyte | The solution of unknown concentration in the flask | HCl or H₂SO₄ |
| Burette | A long graduated tube with a tap at the bottom | 50 mL capacity |
| Pipette | Delivers a fixed volume into the flask | 25 mL |
| Indicator | A substance that changes colour with pH | Phenolphthalein, methyl orange |
| Equivalence point | Acid and base have met in exactly equal moles | A calculated, theoretical point |
| End point | The colour change you actually see | The burette reading |
| Titre | Volume of titrant used up to the end point | End-point reading |
From burette to flask, step by step
In a real laboratory the steps go in a fixed order to get a trustworthy result.
- Rinse the burette with a little of the alkali, so leftover water does not dilute it.
- Fill it and check that no air bubble sits in the tip below the tap. A bubble ruins the reading.
- Pipette exactly 25 mL of acid into the flask and add a few drops of indicator. A white tile under the flask makes the colour change easy to see.
- Record the starting burette reading. Keep your eye level with the meniscus and read the bottom of the curve.
- Open the tap and swirl the flask as you add alkali. Slow down once the colour starts to linger.
- Near the end point add single drops (one drop is about 0.05 mL). Stop at the first colour that lasts and record the final reading.
- Final minus starting reading is the titre. Repeat until you have concordant results, within 0.10 mL, and average them.
Indicators: why the colour changes
An indicator is itself a weak acid or base whose molecule and ion have different colours. As the pH moves, the ratio of the two forms moves, and so does the colour. Each indicator has a short pH range in which this happens.
Phenolphthalein changes between pH 8.2 and 10.0: colourless below, pink above. Methyl orange changes between 3.1 and 4.4: red below, yellow above, orange in between. The coloured bands on the graph in the simulation are exactly these ranges.
| Indicator | Colour in acid | Colour in base | pH range | Good for |
|---|---|---|---|---|
| Phenolphthalein | Colourless | Pink | 8.2 – 10.0 | Strong acid + strong base, weak acid + strong base |
| Methyl orange | Red | Yellow | 3.1 – 4.4 | Strong acid + strong base, strong acid + weak base |
The pH curve: a leap in one drop
Titrate 25 mL of 0.10 M HCl with 0.10 M NaOH and the equivalence point sits at 25.0 mL. For almost the whole run the pH creeps upwards, then near that point it shoots almost straight up.
How big is the jump? One drop (0.05 mL) before the equivalence point the pH is 4.00; one drop after, it is 10.00. That is about seven pH units across a single drop, and it is why one drop flips the indicator completely.
| NaOH added | pH |
|---|---|
| 0.0 mL | 1.00 |
| 10.0 mL | 1.37 |
| 20.0 mL | 1.95 |
| 24.0 mL | 2.69 |
| 24.9 mL | 3.70 |
| 25.0 mL | 7.00 |
| 25.1 mL | 10.30 |
| 26.0 mL | 11.29 |
| 30.0 mL | 11.96 |
| 40.0 mL | 12.36 |
The concentration formula
Molarity is moles per litre. Volume times molarity (in mL, millimoles) gives the amount. At the equivalence point the moles of H⁺ from the acid equal the moles of OH⁻ from the base, and that gives the rule.
For a 1 : 1 reaction like HCl and NaOH it is simply V₁M₁ = V₂M₂. But each H₂SO₄ molecule gives two H⁺, so one mole of acid needs two moles of NaOH, and the mole ratio has to go in.
V₁M₁ = V₂M₂when the acid : base mole ratio is 1 : 1
Mₐ × Vₐ ÷ a = M_b × V_b ÷ ba : b = acid : base coefficients in the equation
Mₐ = M_b × V_b ÷ (n × Vₐ)n = moles of base per mole of acid (1 for HCl, 2 for H₂SO₄)
concentration (g/L) = M × molar massHCl 36.5, H₂SO₄ 98 g/mol
Try it yourself in the simulation
Run these one at a time, and write down a prediction before each one.
- Experiment 1: HCl, phenolphthalein, 0.08 M. Open the tap. Near 20.0 mL the flask turns pink, and the calculated concentration lands close to the true one.
- Experiment 2: pour the whole lot with the tap fully open, then repeat going drop by drop near the end point. Which run has the smaller error?
- Experiment 3: switch to methyl orange. It turns from red to orange-yellow just before the equivalence point, so the calculated concentration comes out slightly low.
- Experiment 4: switch to H₂SO₄ at the same 0.08 M. The equivalence point is now 40.0 mL, exactly double. That is the 1 : 2 ratio.
- Experiment 5: raise the concentration until the end point would lie beyond the burette. The tap shuts at the end of the scale, as a real burette would run out.
Solved problems
Every number here is computed from the simulation’s own model, so you can check it against the screen.
Problem 1: 25 mL of HCl needed 20.40 mL of 0.10 M NaOH. What is the concentration of the HCl?
Rule (1 : 1): M₁ = M₂V₂ ÷ V₁ = 0.10 × 20.40 ÷ 25 = 0.0816 M.
In g/L: 0.0816 × 36.5 = 2.98 g/L.
Problem 2: 25 mL of H₂SO₄ needed 18.50 mL of 0.10 M NaOH. What is the concentration of the H₂SO₄?
Reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. One mole of acid takes two of base.
Millimoles of NaOH = 0.10 × 18.50. The acid is half of that, so M = 0.10 × 18.50 ÷ (2 × 25) = 0.0370 M.
Putting the numbers straight into V₁M₁ = V₂M₂ would give 0.0740 M, twice too high. The correct answer in g/L is 3.63.
Problem 3: how much 0.10 M NaOH neutralises 25 mL of 0.06 M acid?
For HCl: V = 0.06 × 25 ÷ 0.10 = 15.0 mL.
For H₂SO₄ the ratio is 1 : 2, so it takes 30.0 mL. The same concentration, twice the alkali.
Problem 4: what is the pH of 25 mL of 0.10 M HCl after 10 mL and after 30 mL of NaOH?
10 mL: leftover H⁺ = (2.50 − 1.00) mmol ÷ 35 mL = 0.0429 M, so pH = 1.37.
30 mL: past the equivalence point (25.0 mL). Excess OH⁻ = 0.50 ÷ 55 M, which gives pH = 11.96.
Problem 5: how much error does methyl orange cause?
Methyl orange turns in the middle of pH 3.1–4.4. For 0.10 M HCl that pH is reached after 24.91 mL, while the equivalence point is at 25.0 mL.
The error is about 0.36 percent, which sits inside the burette’s own reading error. Phenolphthalein is better still, at 25.006 mL.
Mistakes everyone makes
These are the places that cost the most marks, in exams and in the lab.
- Forgetting the mole ratio: using V₁M₁ = V₂M₂ directly for H₂SO₄ or H₃PO₄.
- Stopping after the end point: a deep pink means extra alkali and a concentration that comes out too high.
- Leaving a bubble in the burette tip, which makes the reading wrong.
- Not rinsing the pipette or burette: the water inside changes the concentration.
- Reading the meniscus from above: read the bottom of the curve with your eye level.
- Doing the titration once: you need at least three close readings.
- Choosing the wrong indicator: with a weak acid and a weak base no indicator gives a sharp end point.
Titration in real life
The method has long left the school lab and reached factories, hospitals and food shops.
- Medicines: tablet makers use titration to check how much active ingredient each batch holds.
- Food and drink: the acetic acid percentage in vinegar, the acidity of juice and how sour milk has become.
- Water testing: the alkalinity and hardness of river or pond water.
- Farming: measuring soil acidity to decide how much lime to add.
- Health: working out how much stomach acid an antacid tablet can neutralise.
Exam corner (SSC, HSC)
Try these yourself first, then check the answers.
- Short questions: What is a titration? How do the end point and equivalence point differ? Why must the burette and pipette be rinsed?
- Numerical: 25 mL of HCl needed 20.40 mL of 0.10 M NaOH. Find the molarity. Answer: 0.0816 M.
- Numerical: 25 mL of H₂SO₄ needed 18.50 mL of 0.10 M NaOH. Answer: 0.0370 M. Did you include the ratio?
- Reasoning: why is phenolphthalein good for a weak acid against a strong base? The solution at equivalence is basic, pH above 7, where its band lies.
- Sketch: draw the pH curve for a strong acid and a strong base and mark the equivalence point at pH 7.
Revision: at a glance
Read this list the night before the exam.
- A titration finds an unknown concentration (analyte) using a solution of known concentration (titrant).
- The end point is the indicator’s colour change; the equivalence point is the theoretical point of equal moles.
- For a 1 : 1 reaction, V₁M₁ = V₂M₂; otherwise bring in the mole ratio.
- For a strong acid and a strong base the equivalence pH is 7, and the curve is almost vertical there.
- The indicator’s pH range must lie inside the steep part of the curve.
- Go drop by drop at the end, read the bottom of the meniscus, and repeat three times.
Frequently asked questions
What is a titration?
A titration is a quantitative method in which a solution of known concentration is added from a burette, drop by drop, to a solution of unknown concentration until the reaction is exactly complete. An indicator changing colour marks that moment.
What is the difference between the end point and the equivalence point?
At the equivalence point the acid and base have reacted in exactly equal moles; it is a theoretical point. The end point is the colour change you can see. With a well-chosen indicator the two are almost the same.
When does V₁M₁ = V₂M₂ work?
When the acid and base react in a 1 : 1 mole ratio, as HCl and NaOH do. For other ratios (H₂SO₄ and NaOH is 1 : 2) divide each side by its coefficient from the balanced equation.
How do I find the concentration in a titration with H₂SO₄?
Mₐ = M_b × V_b ÷ (2 × Vₐ). In the simulation, 25 mL of H₂SO₄ that needs 18.50 mL of 0.10 M NaOH has a concentration of 0.0370 M.
Which indicator should I use?
For a strong acid with a strong base either phenolphthalein or methyl orange works. Use phenolphthalein for a weak acid with a strong base, and methyl orange for a strong acid with a weak base. The rule is that the indicator’s range lies inside the steep part of the curve.
What happens if I overshoot the end point?
There is extra alkali in the flask, so the titre is too large and the calculated concentration comes out higher than the truth. That is why you go drop by drop near the end point.
Keep studying this topic
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