Controls
Choose a solid
View
Readings
- Volume = ⅓πr²h
- 37.70cu. units
- Curved surface area = πrl
- 47.12sq. units
- Total surface area = πr(r + l)
- 75.40sq. units
- Slant height, l = √(r² + h²)
- 5.00units
- Sector angle
- 216.0°
- Litres if the unit is cm
- 0.038
How to use this simulation
- The simulation opens on a cone of radius 3 and height 4. It turns by itself; drag it, or press the arrow keys, to look from any side. The dashed lines are the measured lengths: r, h and the slant height l = 5.
- Pick another solid with the buttons: cube, cuboid, cylinder, cone, sphere or hemisphere. Each has its own sliders (side, length, width, height or radius). The readings panel gives the volume, the curved (or lateral) surface area and the total surface area at once, and they change as you drag.
- Tick “Wireframe” to see through the solid and count its faces and edges. Pause the animation to look at one angle for as long as you like.
- Switch the view to “Unfold the net”. The faces fade into a flat pattern: for the cone, a circle and a sector of angle 216°; for the cylinder, two circles and a rectangle 18.85 wide. The areas of the flat pieces add up to the total surface area.
- Switch the view to “Pour water”. Water from a cone fills a cylinder of the same radius and height, one third per pour. Choose the sphere experiment to see a sphere fill exactly two thirds of its circumscribing cylinder.
- Use the pour slider to stop at any point, then read the filled fraction in the readings. Change r or h and watch the cylinder volume change while the fractions stay put.
Why does an ice-cream cone look so big and hold so little?
Take a paper cup and an ice-cream cone with the same opening and the same height. Fill the cone with water and pour it into the cup. The cup is not full. Pour a second cone: still not full. Only the third pour brings the water to the brim. The simulation does this for you with a cone of radius 3 and height 4: the cone holds 37.70 cubic units, the cylinder holds 113.10, and 113.10 ÷ 37.70 = 3.
That “one third” is no accident, and it is the most useful fact in this chapter. It means you only need to learn one formula for the cylinder and divide by three for the cone. This page lets you see it, then explains it, then uses it to solve the kind of problems that appear in exams and in real life.
Volume and surface area, from zero
Imagine a wooden block. Volume is how many unit cubes you could pack inside it. A block 4 long, 3 wide and 2 tall holds 4 × 3 × 2 = 24 unit cubes, so its volume is 24 cubic units. The unit is cubed because you multiplied three lengths.
Now imagine wrapping the same block in gift paper. The paper you need is the surface area: the area of every face added together. Each face is flat, so you work in squares: square centimetres, square metres. Surface area is a flat quantity living on the skin of a solid, volume is a roomy quantity living inside it.
Some solids have a curved skin. A can has a flat top, a flat bottom and one curved wall. The curved wall alone is the curved surface area (CSA). Everything together is the total surface area (TSA). For a cube or cuboid we usually say lateral surface area for the four walls, ignoring top and bottom.
Words you will meet
Keep this table at hand. Textbooks use slightly different names for the same ideas.
| Term | Meaning |
|---|---|
| Volume | The space inside a solid, in cubic units (cm³, m³) |
| Curved surface area (CSA) | The area of the curved part only, such as the wall of a can |
| Lateral surface area | The area of the side faces of a cube or cuboid, without top and bottom |
| Total surface area (TSA) | The area of the whole outside, curved and flat parts together |
| Radius (r) | The distance from the centre of a circle or sphere to its edge |
| Height (h) | The straight, vertical distance from the base to the top or the tip |
| Slant height (l) | The length along the sloping side of a cone, from the rim to the tip |
| Net | The flat pattern you get by cutting a solid along its edges and unfolding it |
| Hemisphere | Half a sphere, with one curved face and one flat circular face |
All six formulas in one table
Read across the table row by row. Notice how the cylinder is the “parent”: the cone takes a third of its volume, and the sphere and hemisphere are built from r alone.
The same table with numbers
Here are the values for the simulation’s default sizes: side 3 for the cube, 4 × 3 × 4 for the cuboid, and radius 3 (height 4 where there is one) for the rest. Compare each row with the readings panel.
| Solid | Volume | CSA / lateral | TSA |
|---|---|---|---|
| Cube | 27.00 | 36.00 | 54.00 |
| Cuboid | 48.00 | 56.00 | 80.00 |
| Cylinder | 113.10 | 75.40 | 131.95 |
| Cone | 37.70 | 47.12 | 75.40 |
| Sphere | 113.10 | 113.10 | 113.10 |
| Hemisphere | 56.55 | 56.55 | 84.82 |
| Solid | Volume | Curved / lateral area | Total surface area |
|---|---|---|---|
| Cube | a³ | 4a² | 6a² |
| Cuboid | l × w × h | 2h(l + w) | 2(lw + wh + lh) |
| Cylinder | πr²h | 2πrh | 2πr(r + h) |
| Cone | ⅓πr²h | πrl | πr(r + l) |
| Sphere | 4⁄3 πr³ | 4πr² | 4πr² |
| Hemisphere | ⅔πr³ | 2πr² | 3πr² |
Why a cone is one third of a cylinder
Three ways to see it, from the easy one to the deep one.
Pour it
Use the pour view with the cone experiment. The cone and cylinder share radius 3 and height 4. After one pour the cylinder is a third full, after two a two-thirds, after three it is full. So cylinder = 3 × cone, or cone = ⅓ × cylinder.
cone = ⅓ × πr²hsame r and h as the cylinder
Cut a cube into three pyramids
A cube of side 3 has volume 27. Pick one corner and join it to the other seven corners. The cube splits into three identical pyramids, each with a square base of side 3 and height 3. Each pyramid has volume 9, one third of the cube. A cone is a pyramid with infinitely many sides, so the same ⅓ carries over.
Archimedes and the sphere
Put a sphere of radius 3 inside a cylinder that just fits it: radius 3, height 6. Archimedes proved the sphere takes up exactly two thirds of that cylinder. Check: 113.10 ÷ 169.65 = 0.667, which is ⅔. He was so proud of it that he asked for the picture to be carved on his tomb.
sphere = ⅔ × cylinder = ⅔ × πr² × 2r = ⁴⁄₃πr³Archimedes’ result
Unfolding the surface: nets
Surface area is easy when every piece is flat. A net is what a solid becomes when you cut along its edges and lay it down. Switch the simulation to the net view and the pieces fall flat.
Cube and cuboid
A cube is six squares of side 3. Six areas of 9 give 54. A cuboid is three pairs of rectangles, so its total area is 2(lw + wh + lh); for 4 × 3 × 4 that is 80.
Cylinder
Cut the wall of a can straight down and unroll it: you get a rectangle. Its height is h and its width is the circumference of the base, 2πr = 18.85 for r = 3. So the curved area is 2πr × h = 75.40. Add the two circles πr² each and you have the TSA.
Cone
Unroll the cone’s wall and you get a sector of a circle whose radius is the slant height l = √(r² + h²) = 5. Its arc is the rim of the base, so the sector’s angle is 360 × r ÷ l = 216°. The sector’s area is πrl = 47.12; the base circle adds the rest, giving 75.40.
Sphere and hemisphere
A sphere cannot be flattened without tearing, which is why map makers struggle. But Archimedes showed its area equals four circles of the same radius: 4πr² = 113.10 for r = 3. A hemisphere’s curved part is two such circles (2πr²) and its flat face one more, so its TSA is 3πr² = 84.82.
Try it in the simulation
Six short experiments. Predict the answer first, then check it with the readings.
- Choose the cylinder and double r from 3 to 6. The volume grows 4 times, because r is squared. Now double h instead and the volume grows only 2 times.
- Choose the sphere and double its radius. The surface area grows 4 times and the volume 8 times. Lengths double, areas ×4, volumes ×8: that is true for every solid.
- Choose the cone and set r = 6, h = 8. The slant height becomes 10 and the volume 301.59. Every length is doubled, so the volume is 8 times larger than before.
- Choose the cuboid and make all three sliders equal. It turns into a cube, and l × w × h becomes a³.
- Open the cone net and push h very high. The sector gets narrower: a tall thin cone has a small sector angle. Lower h and the sector opens up toward a full circle.
- Run the sphere pour and check that the cylinder stops at the ⅔ mark, not at the top. The remaining third is exactly the volume of a cone of the same size.
Solved problems
Every number below is computed with the same formulas as the simulation.
Problem 1: a water tank
A cylindrical tank has radius 1.2 m and height 2.5 m. How many litres does it hold?
Volume = πr²h = π × 1.2² × 2.5 = 11.31 m³. One cubic metre is 1000 litres, so the tank holds 11.31 × 1000 = 11,310 litres.
Problem 2: paint for a drum
A closed drum has radius 0.35 m and height 1.2 m. One litre of paint covers 12 m². How much paint for 2 coats?
The whole outside is painted, so use the TSA: 2πr(r + h) = 3.41 m². Two coats double that. Paint = 3.41 × 2 ÷ 12 = 0.57 litres.
Problem 3: an ice-cream cone with a scoop
A cone of radius 3 cm and height 10 cm is topped by a hemisphere of the same radius. Find the total volume and the area of the wafer.
Cone: ⅓πr²h = 94.25 cm³. Hemisphere: ⅔πr³ = 56.55 cm³. Total = 150.80 cm³, about 150.80 mL. The wafer is the curved surface of the cone: l = √(3² + 10²) = 10.44 cm, so CSA = πrl = 98.40 cm².
Problem 4: melting a sphere into cones
A solid metal sphere of radius 6 cm is melted and recast into small cones of radius 3 cm and height 4 cm. How many cones?
Melting changes shape, not volume. Sphere: 904.78 cm³. One cone: 37.70 cm³. Number of cones = 904.78 ÷ 37.70 = 24.
Problem 5: a sphere drawn into wire
A metal sphere of radius 3 cm is drawn into a wire of radius 0.1 cm. How long is the wire?
Sphere volume = 113.10 cm³. The wire is a very long cylinder, so volume = πr²h gives h = 113.10 ÷ (π × 0.1²) = 3,600 cm, which is 36 metres.
Problem 6: a fish tank
A glass tank is 80 cm long, 40 cm wide and 50 cm tall. How many litres of water fill it?
Volume = 80 × 40 × 50 = 160,000 cm³. Since 1000 cm³ is one litre, the tank holds 160 litres.
Common mistakes
Almost every lost mark in this chapter is one of these.
- Mixing up CSA and TSA. For the default cone the CSA is 47.12, but the TSA is 75.40: the base circle is missing from the first. Read whether the question wants the “curved” or the “total” surface.
- Using h instead of l in the cone’s area. Using h = 4 instead of l = 5 in πrl gives 37.70, which is about 20% too small. Volume uses h, area uses l.
- Forgetting that 1 m³ is 1000 litres, not 100 litres. And 1 m³ is 1,000,000 cm³, not 1000 cm³.
- Using diameter where the formula wants radius. Halve the diameter first.
- Adding areas of faces that do not exist. A tank that is open on top has no lid to paint; a pipe has no end faces in its CSA.
- Mixing units in one formula, such as r in metres and h in centimetres. Convert everything first.
Where you will use this
Mensuration is one of the most practical chapters in school mathematics.
- Water tanks, silos and drums are cylinders. Engineers turn their volume into litres or tonnes.
- Tents, funnels, traffic cones and party hats are cones. Tailors cut the cloth as a sector, which is exactly the net you saw.
- Footballs, bubbles and planets are spheres. Domes and bowls are hemispheres.
- Room painting, tiling and packing all need surface area; cooking pots and concrete need volume.
- Scaling matters in biology: a small animal has more surface area per unit of volume, so it loses heat faster.
Exam corner: CBSE and school boards
Questions follow a handful of patterns: find a volume or area, combine two solids, melt and recast, or convert to litres. For board exams the value π = 22/7 is common when r is a multiple of 7.
A typical board question
A cone has radius 7 cm and height 24 cm. Find its slant height, curved surface area, total surface area and volume (π = 22/7).
Slant height l = √(7² + 24²) = 25 cm. CSA = πrl = 550 cm². TSA = πr(r + l) = 704 cm². Volume = ⅓πr²h = 1,232 cm³.
One with π as a decimal
A cylinder has radius 7 cm and height 20 cm. Its volume is 3,078.76 cm³ and its total surface area is 1,187.52 cm² (π = 3.1416).
Revision summary
Read this list once before every test.
- Volume is in cubic units, surface area in square units.
- Cylinder: V = πr²h, CSA = 2πrh, TSA = 2πr(r + h).
- Cone: V = ⅓πr²h, CSA = πrl, TSA = πr(r + l), with l = √(r² + h²).
- Sphere: V = ⁴⁄₃πr³, area 4πr². Hemisphere: V = ⅔πr³, CSA 2πr², TSA 3πr².
- Cube: V = a³, TSA = 6a². Cuboid: V = lwh, TSA = 2(lw + wh + lh).
- Cone = ⅓ cylinder; sphere = ⅔ of its circumscribing cylinder.
- Melting or recasting keeps the volume the same.
- 1 m³ = 1000 litres; 1000 cm³ = 1 litre.
Frequently asked questions
What is the difference between volume and surface area?
Volume measures the space inside a solid in cubic units; surface area measures the outside skin in square units. The default cone holds 37.70 cubic units and has a total surface area of 75.40 square units.
Why is the volume of a cone one third of a cylinder?
Because pouring a cone of the same radius and height into a cylinder fills it exactly one third each time, so three cones fill it. The cube-into-three-pyramids picture and calculus both give the same ⅓.
What is the slant height and when do I use it?
The slant height l is the distance along the sloping side of a cone from the rim to the tip, l = √(r² + h²). Use it for the curved surface area πrl. For the default cone r = 3 and h = 4, l = 5.
How do I convert cubic metres to litres?
Multiply by 1000. One cubic metre is 1000 litres. A volume in cubic centimetres is divided by 1000 to get litres, since 1000 cm³ equal one litre.
What is the surface area of a hemisphere?
The curved surface is 2πr². If the flat circular base counts, add πr² for a total of 3πr². For r = 3 those are 56.55 and 84.82.
What is a net of a solid?
A net is the flat shape you get by cutting a solid along some edges and unfolding it. The areas of all the pieces of the net add up to the total surface area. A cylinder’s net is a rectangle and two circles.
Keep studying this topic
The animation made the idea click; now turn it into marks. Syllabus, suggestions, textbooks and admission-test guides are below.
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Class 9-10 Mathematics textbook
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রচনা: কৃত্রিম বুদ্ধিমত্তা (in Bangla)
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