Use the plus and minus buttons to change coefficients. Find an element whose two bars differ, fix it, then re-check the others. When every bar is green the equation is balanced.
Controls
Choose a reaction
Making water
Change the coefficients
Readings
- Status
- Not balanced yet
- Sum of coefficients
- 3
- Atoms of H
- 2 : 2
- Atoms of O
- 2 : 1
- Mass on the left
- 34.0u
- Mass on the right
- 18.0u
How to use this simulation
- Start with H₂ + O₂ → H₂O in the reaction picker. Every coefficient is 1, and the bars show oxygen with 2 atoms on the left and 1 on the right, so that row is marked as a mismatch.
- Pick an element whose two bars differ and change one coefficient. Each press of plus draws another copy of that molecule and the bars grow. Change one coefficient at a time.
- When one element matches, re-check the others. A single change can shift several counts at once, so balancing is a loop, not a straight line.
- When every row is green the status reads “Balanced”. If it says “Balanced, but can be simpler”, divide every coefficient by the same number.
- If you get stuck press “Show the answer”, then reset and try it yourself. Work through all five reactions.
What does a bicycle need? Count it
Say you are building a bicycle. One bike takes 1 frame, 2 wheels, 1 seat and 2 pedals. If a shop sells you “one wheel and one frame”, you would ask where the second wheel is. To build a bike, the wheel has to be counted twice.
A chemical equation works the same way. In a reaction the atoms are rearranged, like bike parts being bolted into something new. But no part falls out of the sky and none vanishes. Whatever number of atoms you had before the reaction, you have after it.
When we first write an equation we often just list the formulas: H₂ + O₂ → H₂O. That is a skeleton equation. It has two oxygen atoms on the left and one on the right, as if an oxygen atom had disappeared. Adding coefficients to close that gap is what balancing is.
Why equations have to balance
The reason is the law of conservation of mass. The French chemist Lavoisier weighed everything before and after reactions in sealed vessels and showed the total mass never changed. In short: in a chemical reaction, mass is neither created nor destroyed.
If mass does not change, neither can the number of atoms, because mass comes from atoms. So whatever number of atoms of an element sits on the left, the same number must sit on the right. One unmatched element and the equation is unfinished.
There is a bonus. The coefficients tell you the ratio in which substances react. Without that ratio you cannot work out how much raw material a factory needs to buy.
Key terms
Most mix-ups in balancing come from coefficients and subscripts. Read this table once, carefully.
| Term | Meaning | Example |
|---|---|---|
| Reactant | A substance on the left of the arrow, which reacts | H₂, O₂ |
| Product | A substance on the right of the arrow, which forms | H₂O |
| Coefficient | The number in front of a formula: how many copies of that molecule | 2H₂ means 2 molecules |
| Subscript | The small number inside a formula: atoms in one molecule | the 2 in H₂O |
| Skeleton equation | Formulas written, coefficients not yet added | H₂ + O₂ → H₂O |
| Balanced equation | Every element has equal atoms on both sides | 2H₂ + O₂ → 2H₂O |
The method in five steps
You do not need a formula to memorise. Every equation yields to the same routine. It is called inspection, or trial and error, but with a few rules it takes very few tries.
The steps
Work through them in this order each time.
- 1. Write the skeleton equation and count the atoms of each element on each side.
- 2. Start with an element that appears in only one formula on each side. Oxygen and hydrogen often appear in several, so leave them for last.
- 3. Put a coefficient in front of a formula to fix the short side. The least common multiple of the two counts is the quickest target.
- 4. Changing one coefficient changes other counts, so recount every element.
- 5. Finally check whether all coefficients share a factor. If they do, divide it out to reach the smallest whole numbers.
Five equations, one step at a time
These are the same five reactions the simulation offers. The counts below match its bars exactly.
Reaction 1: making water, H₂ + O₂ → H₂O
At the start hydrogen is 2 : 2 and oxygen 2 : 1. Oxygen is short on the right, so put 2 in front of H₂O. Oxygen now matches, but hydrogen is 2 on the left and 4 on the right.
Fix hydrogen by putting 2 in front of H₂. Result: 2H₂ + O₂ → 2H₂O. Hydrogen 4 : 4, oxygen 2 : 2.
| Element | Left | Right | Match |
|---|---|---|---|
| H | 4 | 4 | ✓ |
| O | 2 | 2 | ✓ |
Reaction 2: burning methane, CH₄ + O₂ → CO₂ + H₂O
Carbon is already 1 : 1. Hydrogen is 4 on the left and 2 on the right, so put 2 in front of H₂O. Oxygen on the right is now 2 from CO₂ plus 2 from water, 4 in all.
Put 2 in front of O₂ and the left has 4 oxygen atoms. Done: CH₄ + 2O₂ → CO₂ + 2H₂O. This is the equation for biogas or natural gas burning.
| Element | Left | Right | Match |
|---|---|---|---|
| C | 1 | 1 | ✓ |
| H | 4 | 4 | ✓ |
| O | 4 | 4 | ✓ |
Reaction 3: iron rusting, Fe + O₂ → Fe₂O₃
Oxygen is 2 on the left and 3 on the right. An even number against an odd one calls for the least common multiple, 6: put 3 in front of O₂ and 2 in front of Fe₂O₃. Both sides now have 6 oxygen atoms.
That makes 4 iron atoms on the right against 1 on the left, so put 4 in front of Fe: 4Fe + 3O₂ → 2Fe₂O₃. It also explains why rusty iron gets heavier: the metal pulls oxygen out of the air.
| Element | Left | Right | Match |
|---|---|---|---|
| Fe | 4 | 4 | ✓ |
| O | 6 | 6 | ✓ |
Reaction 4: aluminium and acid, Al + HCl → AlCl₃ + H₂
Chlorine is 1 on the left and 3 on the right. A 3 in front of HCl fixes chlorine but leaves hydrogen at 3 against 2. The least common multiple of 3 and 2 is 6.
So HCl gets 6 and H₂ gets 3. To match 6 chlorine atoms AlCl₃ needs 2, which gives 2 aluminium atoms, so Al gets 2: 2Al + 6HCl → 2AlCl₃ + 3H₂.
| Element | Left | Right | Match |
|---|---|---|---|
| Al | 2 | 2 | ✓ |
| H | 6 | 6 | ✓ |
| Cl | 6 | 6 | ✓ |
Reaction 5: burning propane (cooking gas), C₃H₈ + O₂ → CO₂ + H₂O
Step by step: 3 carbon atoms means 3 in front of CO₂. 8 hydrogen atoms means 4 in front of H₂O. The right side now holds 10 oxygen atoms, so O₂ gets 5.
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. Oxygen goes last because it sits in two formulas on the right; balancing it early would mean redoing it again and again.
| Element | Left | Right | Match |
|---|---|---|---|
| C | 3 | 3 | ✓ |
| H | 8 | 8 | ✓ |
| O | 10 | 10 | ✓ |
Does the mass really stay the same? Check
If the atoms match, the mass has to match. With the textbook atomic masses (H = 1, C = 12, O = 16, Al = 27, Cl = 35.5, Fe = 56) you can prove it.
| Reaction | Sum of coefficients | Mass on the left (u) | Mass on the right (u) |
|---|---|---|---|
| Making water | 5 | 36 | 36 |
| Burning methane | 6 | 80 | 80 |
| Iron rusting | 9 | 320 | 320 |
| Aluminium and acid | 13 | 273 | 273 |
| Burning propane (cooking gas) | 13 | 204 | 204 |
Try it yourself in the simulation
Run these experiments one after another and the idea will stick.
- Experiment 1: choose making water and watch oxygen. It starts at 2 : 1. Set H₂O to 2. Does the row turn green? What happened to the hydrogen row?
- Experiment 2: double every coefficient on purpose. All rows are green, yet the status says “Balanced, but can be simpler”. A balanced equation should still use the smallest whole numbers.
- Experiment 3: choose rusting and fix oxygen first. See why 3 and 2 leave iron unmatched, then set Fe.
- Experiment 4: choose propane and balance oxygen last. Then try oxygen first and count how many times you have to redo it.
- Experiment 5: after each equation compare “Mass on the left” and “Mass on the right”. They are always equal.
Mistakes everybody makes
These cost the most marks in exams.
- Changing a subscript to force a match: turning H₂O into H₂O₂ writes a different substance.
- Forgetting that a coefficient multiplies every atom in the formula, not only the first.
- Stopping after one element matches: a new coefficient can unbalance one you already fixed.
- Writing a coefficient of 1: “1H₂O” is unnecessary, a blank already means one.
- Not checking for a common factor: 4H₂ + 2O₂ → 4H₂O is balanced, but the simplest form is 2H₂ + O₂ → 2H₂O.
Balanced equations in real life
A balanced equation is not just a textbook exercise; kitchens and factories both lean on it.
- Cooking gas: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O says each propane molecule needs 5 oxygen molecules. In a sealed room the oxygen runs low, combustion turns incomplete and poisonous carbon monoxide forms.
- Fertiliser plants: each step of urea manufacture is sized from the coefficients, so tonnes of ammonia are ordered by arithmetic, not by guess.
- Engines: the fuel-to-air ratio is set from the combustion equation.
- Rust: the iron equation shows why painted steel lasts, because paint keeps oxygen away from the metal.
- Medicine: the amount of each ingredient in a batch follows the coefficients.
Exam corner (CBSE, NCERT class 10 and others)
Questions here are almost always “balance this” or a definition. Try the three below, then check against the answers.
- Short answer: state the law of conservation of mass. What is the difference between a coefficient and a subscript?
- Trick: ethane first asks for 3.5 molecules of O₂, a fraction. Multiply the whole equation by 2 and every coefficient becomes a whole number.
- In long answers, show the atom-count table as well as the final equation; the working earns marks.
| Skeleton equation | Balanced equation | Check |
|---|---|---|
| Fe + H₂O → Fe₃O₄ + H₂ | 3Fe + 4H₂O → Fe₃O₄ + 4H₂ | Fe 3, O 4, H 8 : 8 |
| Na + H₂O → NaOH + H₂ | 2Na + 2H₂O → 2NaOH + H₂ | Na 2, O 2, H 4 : 4 |
| C₂H₆ + O₂ → CO₂ + H₂O | 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O | C 4, H 12, O 14 : 14 |
Revision: at a glance
Read this list the night before the exam.
- Atoms are neither created nor destroyed, so each element has equal atoms on both sides.
- Change coefficients only, never subscripts.
- Balance the element in the fewest formulas first; oxygen and hydrogen last.
- After every change, recount all elements.
- Finish by reducing the coefficients to the smallest whole numbers.
- Coefficients are also mole ratios: 2H₂ + O₂ → 2H₂O means 2 mol H₂ and 1 mol O₂ give 2 mol of water.
Frequently asked questions
What does balancing a chemical equation mean?
It means placing coefficients in front of the reactants and products so every element has the same number of atoms on both sides of the arrow. Balancing H₂ + O₂ → H₂O gives 2H₂ + O₂ → 2H₂O.
Why must chemical equations be balanced?
Because of the law of conservation of mass: atoms are not created or destroyed in a reaction. An unbalanced equation breaks that law, and the coefficients also supply the mole ratios needed for calculations.
What is the difference between a coefficient and a subscript?
A coefficient sits in front of a formula and counts how many molecules or formula units are involved. A subscript sits inside the formula and counts the atoms of one element in a single molecule. Only coefficients may be changed when balancing.
What is the easiest way to balance an equation?
Count atoms on both sides, start with the element in the fewest formulas, leave oxygen and hydrogen for last, recount after every change, and reduce to the smallest whole numbers. C₃H₈ + 5O₂ → 3CO₂ + 4H₂O is balanced this way.
Can a coefficient be a fraction?
Halfway through the working, yes: ethane needs 3.5 molecules of O₂. In the final equation coefficients are whole numbers (there is no half a molecule), so multiply the whole equation through to clear the fraction.
Is the equation wrong if I double every coefficient?
The atoms still balance, so it is not chemically wrong, but convention is to give the smallest whole-number coefficients. Many exams deduct marks for a reducible answer.
Why does mass stay the same in a reaction?
Atoms are only rearranged, never lost, and each kind of atom has a fixed mass, so the total mass cannot change. In the table above the left and right masses of all five reactions are identical.
Keep studying this topic
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